4y^2-2=29

Solution for 4y^2-2=29 equation:

4y^2-2=29

We move all terms to the left:

4y^2-2-(29)=0

We add all the numbers together, and all the variables

4y^2-31=0

a = 4; b = 0; c = -31;
Δ = b2-4ac
Δ = 02-4·4·(-31)
Δ = 496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{496}=\sqrt{16*31}=\sqrt{16}*\sqrt{31}=4\sqrt{31}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{31}}{2*4}=\frac{0-4\sqrt{31}}{8}
=-\frac{4\sqrt{31}}{8}
=-\frac{\sqrt{31}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{31}}{2*4}=\frac{0+4\sqrt{31}}{8}
=\frac{4\sqrt{31}}{8}
=\frac{\sqrt{31}}{2}
$